Inner joins step 1. Counting newspaper subscribers


#1

If you had difficulty to understand it. here is the answer:
select count(*) from newspaper;

Yaa! I know.
:expressionless:

And the full answer for #3 is:
select count() from newspaper;
select count(
) from online;

SELECT count(newspaper.id)
FROM newspaper JOIN online
ON newspaper.id = online.id;


#2

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