I'm testing code and I"m not sure what the issue is

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#1

The purpose of this code is to see whether or not there are an equal number of 'x’s and 'o’s.

def xo(s):
    if s.count('x') == s.count('o'):

        return True
    else:
        return False

It passed most of the tests but failed 4:

xo(roxopooooUtLooxhdoxxxQoxNoxCxokoxooxxGxASxfxEooooJbmxxxxx) should be True

xo(xxxxxooxxoooxbooxxxoxoxoxxxoxxxoxoxoooxxoxxAxooooo) should be False

xo(JhkxxxbGxdQxxxpxAxxooxrxmNooLofxxCooxExo) should be False

And I guess my function is or is not case sensitive. I can’t tell

#2

It shouldn’t need to be case sensitive since all the tests use x and o.

If you did want to make it case insensitive,

def xo(s):
    s = s.lower()
    # ...
#3

If I run your code with the test cases you’ve posted, I get the results you’re expecting…

Not sure why you aren’t.

It’s case sensitive, unless you change it how @mtf has demonstrated. :slight_smile:

>>> 'x' == 'X'
False
#4

@jaccobtw all of the above, … and, those arguments (xoooxx) etc, must be strings.

#5

@jaccobtw, a bit of extra material to peek at once you have this function going to your satisfaction:

def xo(s):
    if s.count('x') == s.count('o'):
        return True
    else:
        return False

… can be written a bit more concisely as

def xo(s):
    if s.count('x') == s.count('o'):
        return True      # The function halts when return is reached
    return False

… and even more so (maybe even Pythonic!):

def xo(s):
    return s.count('x') == s.count('o')       # s.count('x') == s.count('o') 
                                              # returns True or False all by itself, 
                                              # ... since it is a boolean comparison
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#6

…

D’you know, I just chucked the test cases into a list so I could iterate over them to check the code… didn’t even think about the ''!

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