I have to celebrate you baby, intro to objects question 4


#1



https://www.codecademy.com/en/courses/spencer-sandbox/0/4?curriculum_id=506324b3a7dffd00020bf661


So I am not returning something right...


var getReview = function (movie) {
    
    switch(movie){
        case "Toy Story 2":
            console.log("Great story. Mean prospector.");
            break;
        case "Finding Nemo":
            console.log("Cool animation and funny turtles.");
            break;
        case "The Lion King":
            console.log("Great songs");
            break;
        default:
         console.log("I don't know!");
         break;
         
    }
    return getReview;
};


#2

@ajaxpro26305,
Remove the code-line

You will have to use the exact text's as mentioned in the Instructions....
And in the Instructionsthey ask you to use the return statement
instead of the console.log() Method.

Please read

the FUNCTION talk

var myFunc = function( param1, param2) {
       //Begin of  anonymous FUNCTION-BODY
       //VARIABLE -myFunc- has an -anonymous function- assigned
       //this -anonymous function- has 2 PARAMETERS param1 and param2
       //param1 and param2 PARAMETERS are used 
       //as -local- VARIABLES throughout the FUNCTION-BODY

      console.log( param1 + " and " + param2 ) ;

      //End of anonymous FUNCTION-BODY
};

If you want to call/execute the anonymous function
you will have to add a pair of parentheses to the variable myFunc
like
myFunc();
As the anonymous function was defined
as having 2 parameters
you have to provide 2 arguments
in our case 2 string VALUES "Alena" and "Lauren"
like
myFunc("Alena","Lauren");

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++

function with 1 parameter using return-statement

var myFunction = function( param1 ) {
       //Begin of FUNCTION-BODY
       //myFunction =function= has 1 PARAMETER param1
       //this param1 PARAMETER is used as a -local- VARIABLE
       //throughout the FUNCTION-BODY

      return param1;

      //End of FUNCTION-BODY
      };

you have defined a myFunction function
which takes 1 parameter param1
this param1 parameter is used
as a variable throughout the FUNCTION-BODY.

If you want to call/execute this myFunction function
and this myFunction function was defined
as having 1 parameter param1
you will have to provide 1 argument
in our case a "number VALUE" 4
myFunction( 4 );

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

============================================

As you are using the return-statement in your myFunction function
you will only get a return-value no-display.
You can however capture this return-value in a variable
and then use the console.log()-method to do a display.

var theResult = myFunction( 4 );
console.log( theResult );

OR directly

console.log( myFunction( 4 ) );

#3

Here's your answer

var getReview = function (movie) {
switch(movie) {
case "Toy Story 2":
return("Great story. Mean prospector.");
case "Finding Nemo":
return("Cool animation, and funny turtles.");
case "The Lion King":
return("Great songs.");
default:
return("I don't know!");
}
};

getReview("NAME OF THE MOVIE - ENTER HERE");