I have to celebrate you baby. Help, Illegal Return Statement


#1

I keep getting "Illegal return statement" when I try to run this code. Is there something I'm missing in the switch itself? Thank you in advance.

code:

var getReview = function (movie) {

};
switch(movie) {
case "Toy Story 2":
return "Great story. Mean prospector.";
break;
case "Finding Nemo" :
return "Cool animation, and funny turtles.";
break;
case "The Lion King" :
return "Great songs.";
break;
default:
return "I don't know!";
};
getReview("Finding Nemo");


#2

@byteslayer99312,
In your code you use

var getReview = function (movie) {

};

you have directly closed the getReview function,
and
thus you will get the error 'Illegal Return Statement'
as a return statement can only be used INSIDE a function.


#3

I removed }; and received an "unexpected end of statement" and with only } I'm back at "Illegal Return Statement."

Do I have to do something in the main body of my code that would be prevent the code from running?


#4

@byteslayer99312,

You will have to place the switch()
in your FUNCTION-BODY
like

var getReview = function (movie) {
  switch() {
  }
};

#5

@byteslayer99312,

the FUNCTION talk

var myFunc = function( param1, param2) {
       //Begin of  anonymous FUNCTION-BODY
       //VARIABLE -myFunc- has an -anonymous function- assigned
       //this -anonymous function- has 2 PARAMETERS param1 and param2
       //param1 and param2 PARAMETERS are used 
       //as -local- VARIABLES throughout the FUNCTION-BODY

      console.log( param1 + " and " + param2 ) ;

      //End of anonymous FUNCTION-BODY
};

If you want to call/execute the anonymous function
you will have to add a pair of parentheses to the variable myFunc
like
myFunc();
As the anonymous function was defined
as having 2 parameters
you have to provide 2 arguments
in our case 2 string VALUES "Alena" and "Lauren"
like
myFunc("Alena","Lauren");

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++

function with 1 parameter using return-statement

var myFunction = function( param1 ) {
       //Begin of FUNCTION-BODY
       //myFunction =function= has 1 PARAMETER param1
       //this param1 PARAMETER is used as a -local- VARIABLE
       //throughout the FUNCTION-BODY

      return param1;

      //End of FUNCTION-BODY
      };

you have defined a myFunction function
which takes 1 parameter param1
this param1 parameter is used
as a variable throughout the FUNCTION-BODY.

If you want to call/execute this myFunction function
and this myFunction function was defined
as having 1 parameter param1
you will have to provide 1 argument
in our case a "number VALUE" 4
myFunction( 4 );

some quotes from the outer-world:

**argument is the value/variable/reference being passed in,
parameter is the receiving variable used within the function/block**

OR

**"parameters" are called "formal parameters",
while "arguments" are called "actual parameters".**

============================================

As you are using the return-statement in your myFunction function
you will only get a return-value no-display.
You can however capture this return-value in a variable
and then use the console.log()-method to do a display.

var theResult = myFunction( 4 );
console.log( theResult );

OR directly

console.log( myFunction( 4 ) );

#6

Worked! Thank you!!!!