I get "uncaught syntaxError: unexpected token Catch" when I run my code

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#1

I have been following the instructions for this exercise, but when I write the code for the if statement (see below) I get the above error message. I’ve added in the code that I have done so far. Hope you can help me.

// Add AJAX functions here:
const getVenues = async() => {
const city = input.val(); const urlToFetch = `{url}{city}&limit=10&client_id={clientId}&client_secret=${clientSecret}&v=20200219`;

try {
const response = await fetch(urlToFetch);
if(response.ok){
const jsonResponse = await response.json();
console.log(jsonResponse);
}
catch (error)
{
console.log(error);
};
const venues =jsonResponse.response.groups[0].items;
console.log(venues);
}

#2

Your catch is inside your try. Therefore you got the unexpected token Catch error. I don’t know how you implement indentation in your syntax but that would have aided you in this debugging.

// Add AJAX functions here:
const getVenues = async() => { // opens async
  const city = input.val(); 
  const urlToFetch = `{url}{city}&limit=10&client_id={clientId}&client_secret=${clientSecret}&v=20200219`;

  try { // opens try
    const response = await fetch(urlToFetch);
    if(response.ok) { // opens if statement
      const jsonResponse = await response.json();
      console.log(jsonResponse); 
    } // closes if statement
  // expects a closing } for try yet finds catch, causing the error  
    catch (error) { // opens catch
      console.log(error);
    }; // closes catch
    const venues =jsonResponse.response.groups[0].items;
    console.log(venues);
    } // should close the async yet closes the try
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#3

It could very well be it was indented, and we simply can’t tell because of the lack of proper formatting. :slight_smile:

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