I don't understand my mistake


#1

<PLEASE USE THE FOLLOWING TEMPLATE TO HELP YOU CREATE A GREAT POST!>

<Below this line, add a link to the EXACT exercise that you are stuck at.>
https://www.codecademy.com/courses/javascript-beginner-en-Bthev-mskY8/1/2?curriculum_id=506324b3a7dffd00020bf661

<In what way does your code behave incorrectly? Include ALL error messages.>
Apparently its syntactically invalid but I don’t understand my mistake.

Error message: "
Oops, try again. There was a problem with your syntax."

```

/var userChoice = prompt(“Do you choose rock, paper or scissors?”);
var computerChoice = Math.random();
if (computerChoice < 0.34) {
computerChoice = “rock”;
} else if(computerChoice <= 0.67) {
computerChoice = “paper”;
} else {
computerChoice = “scissors”;
} console.log("Computer: " + computerChoice);
/
var compare = function(userChoice,computerChoice) {
if (userChoice === computerChoice) {

    return("The result is a tie!");
} else if (userChoice = "rock") {
    if (computerChoice === "scissors"{
        return("rock wins")
    } else {
        return("paper wins")
    }
}

}

<do not remove the three backticks above>

#2

Instead of using userChoice and computerChoice, use choice1 and choice2, as you are in a function.


#3

copy & paste it

var userChoice = prompt(" rock, paper or scissors?");
var computerChoice = Math.random();
if (computerChoice < 0.34) {
computerChoice = “rock”;
} else if(computerChoice <= 0.67) {
computerChoice = “paper”;
} else {
computerChoice = “scissors”;
} console.log("Computer: " + computerChoice);

var compare = function (choice1, choice2){
if (choice1 == choice2) {
return “The result is a tie!”;
}
else if(choice1 == “paper”)
{
if (choice2 == “rock”) {return “paper wins”;}
else {return “rock wins”;}

}else if (choice1 == “scissors”)
{
if(choice2 == “rock”) {return “rock wins”;}
else {return “scissors wins”;}
}

else if (choice1 == “rock”){
if(choice2 == “scissors”) {return “rock wins”;}
else {return “scissors wins”;}
}
}

compare(userChoice, computerChoice);