I don't think I did this part of "thread shed" in the python 3 course in the proper manner

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#1

Here is my code up until the point I think I did something weird in this exercise:

#print(daily_sales)

daily_sales_replaced = daily_sales.replace(";,;", ";")

#print(daily_sales_replaced)

daily_transactions = daily_sales_replaced.split(",")

#print(daily_transactions)

daily_transactions_split = []

for i in range(len(daily_transactions)):

  splitted = daily_transactions[i].split(";")

  daily_transactions_split.append(splitted)

#print(daily_transactions_split)

transactions_clean = []

for index in range(len(daily_transactions_split)):

  for words in daily_transactions_split[index]:

    spliited = words.strip()

    transactions_clean.append(spliited)

print(transactions_clean)

customers = []

sales = []

thread_sold = []

for index in range(len(transactions_clean)):

  if index % 4 == 0:

    customers.append(transactions_clean[index])

  elif (index - 1) % 4 == 0:

    sales.append(transactions_clean[index])

  elif (index - 2) % 4 == 0:

    thread_sold.append(transactions_clean[index])

The output of transactions_clean was not a 2d list. I got the impression after reading through my tasks that it was meant to be a 2d list with a name, sale, colour thread and date each in its own separate list inside the 2d list.

As it turns out I was fine and managed to get the lists for customers, sales, and threads sold correct anyway. But I’m just wondering now after finishing the exercise how I would have simultaneously made a list which cleaned up daily_transactions_split with strip() and preserved the 2d nature of daily_transactions_split.

Thanks in advance

#2

While it is certainly possible, it would be very convoluted and require extra logic, and process time. Simplifying the list, then splitting into the three is simple and straight forward.