# I don't know what's wrong with my code

#1

Hello. I got a little trouble here. I kept getting "paper" as my result, but I still don't know why it came out this way.
Here is my code.

var userChoice= prompt("Do you choose rock, paper or scissors?")
var computerChoice= Math.random()
console.log(computerChoice)
if (computerChoice<=.33)
{
computerChoice=("rock");
}
else if (.34<=computerChoice<=.66)
{
computerChoice=("scissors");
}
else (.67<=computerChoice<1.0)
{
computerChoice=("paper");
}

Can anyone help me with it?? I appreciate it!

#2

The Math.random() method will deliver a number with a value
in the range of 0_(included)_ upontill 0.9999_(1 excluded)_.

As you will have to divide the number range form 0_(inclusive)_ to 0,9999_(so 1 excluded)_
into 3 equal partitions
we have to use an if else-if else statement.
The if else-if else skeleton looks like:

``````    if (conditionA) {
//conditionA is true
} else if (conditionB) {
//conditionA is false
//conditionB is true
} else {     // <=== !! Takes NO condition-statements !!
//conditionA is false
//conditionB is false
}``````

following the Instructions the conditions would be:
1. If computerChoice is between 0 and 0.33, make computerChoice equal to "rock".
( 0 <= computerChoice && computerChoice <= 0.33) which we capture at the IF using
( computerChoice <= 0.33)

1. If computerChoice is between 0.34 and 0.66, make computerChoice equal to "paper".
( 0.33 < computerChoice && computerChoice < 0.67) which we capture at the ELSE IF as
( computerChoice < 0.67 )

2. If computerChoice is between 0.67 and 1, make computerChoice equal to "scissors".
( 0.67 <= computerChoice && computerChoice < 1) , you reached the ELSE level
you can asume that computerChoice is greater equal to 0.67,
the ELSE does NOT take a condition, just write your code.

#3

I got it right now!! Thank you very much!!