def cube(number):

return number *2

by_three(number):

if cube(number) % 3 == 0:

print "nao e divisivel"+cube(number)

else:

print "number nao e"+by_three(number)

def cube(number):

return number *2

by_three(number):

if cube(number) % 3 == 0:

print "nao e divisivel"+cube(number)

else:

print "number nao e"+by_three(number)

The term **cube** means, 'to the power of three'.

```
def cube(number):
return number ** 3
```

The exercise asks us to cube any number that is divisible by 3.

```
def by_three(number):
if number % 3 == 0:
print cube(number)
```

Now we need to check this. Please post a link to the exercise you are on. Thank you.