# How "not again" functions?

#1

in fact, i don't understand how "Not again"code functions?
elif(board[guess_row][guess_col] == "X"):
print "You guessed that one already."

``````from random import randint
board = []

for x in range(5):
board.append(["O"] * 5)
def print_board(board):
for row in board:
print " ".join(row)
print "Let's play Battleship!"
print_board(board)

def random_row(board):
return randint(0, len(board) - 1)
def random_col(board):
return randint(0, len(board[0]) - 1)
ship_row = random_row(board)
ship_col = random_col(board)

for turn in range(4):
print "Turn",turn+1
guess_row = int(raw_input("Guess Row:"))-1
guess_col = int(raw_input("Guess Col:"))-1
if guess_row == ship_row and guess_col == ship_col:
print "Congratulations! You sunk my battleship!"
print_board(board)
break
else:
if (guess_row < 0 or guess_row > 4) or\
(guess_col < 0 or guess_col > 4):
print "Oops, that's not even in the ocean."
elif(board[guess_row][guess_col] == "X"):
print "You guessed that one already."
else:
print "You missed my battleship!"
board[ship_row][ship_col] = "X"
if turn==3:
print "Game Over"
print_board(board)``````

#2

When an unoccupied cell is chosen, it gets new content, an `'X'`. When a subsequent guess matches the same cell, we are told so, and guess again.

We are guessing a row, and a column. That gives us two vectors, hence two subscripts.

``board[guess_row]{guess_col]``

The normal content is `'O'`. An already guessed cell will have an `'X'`.

``````        elif board[guess_row][guess_col] == "X":
print "You guessed that one already."``````

#3

i get it~ thank you:grin:

#4

This topic was automatically closed 7 days after the last reply. New replies are no longer allowed.