How is Everybody Doing?


#1

The answer is B but error is still come out.

Oops, try again. One of the following is missing or broken when we tried to use it: alice, lloyd, tyler, students, get_class_average, get_letter_grade

lloyd = {
"name": "Lloyd",
"homework": [90.0, 97.0, 75.0, 92.0],
"quizzes": [88.0, 40.0, 94.0],
"tests": [75.0, 90.0]
}
alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.0, 97.0]
}
tyler = {
"name": "Tyler",
"homework": [0.0, 87.0, 75.0, 22.0],
"quizzes": [0.0, 75.0, 78.0],
"tests": [100.0, 100.0]
}

Add your function below!

def average(numbers):
total = float(sum(numbers))
result = total / len(numbers)
return result

def get_average(student):
homework = average(student['homework']) * 0.1
quizzes = average(student['quizzes']) * 0.3
tests = average(student['tests']) * 0.6

students_score = homework + quizzes + tests
return students_score

def get_letter_grade(score):


if score >= 90 :
    print 'A'

elif score >=80 :
    print 'B'
    
elif score >= 70 :
    print 'C'
    
elif score >= 60 :
    print 'D'
    
else :
    print 'F'

def get_class_average(students):
results = []

for student in students:
    results.append(get_average(student))


return get_letter_grade(average(results))


get_class_average([lloyd,alice,tyler])


#2

This works:
students = [lloyd, alice, tyler]
print get_class_average(students)
print get_letter_grade(get_class_average(students))


#3

thanks landrags .. I have used your way and it works
but still I am not convinced why these unreliable disturbance happene!


#4

are we supposed to define the elements of students list as strings or a list of dictionaries?