Recall that a for loop can take a list like board and the variable becomes the next item in that list every time it loops. So if we write for item in list_name:, item becomes each item in the list called list_name.
Then inside the for loop we simply print that item by doing print item.
With our board, we’d like to print each row, so by filling in those spots in the for loop template, we should get something along the lines of:
def print_function(list_input):
for item in list_input:
print item
print_function(my_list)
At the end, be sure to call our new function and pass it the board!
The function is not doing the printing of None, functions return None in case of absence of a return keyword, if you then decide to print the returned result, you indeed get None printed
but without any code we get to see, that is the most logic guess we can do
I got the same result in my terminal, which logically, is how I got here in the first place. It sounds like, according to stetim94, and since the project is letting me continue, this is not presenting a real problem at the current juncture in the program. For clarity and thoroughness, I just wanted to include a sample of my code, which I assume is probably similar to cassepipe’s.
#Here’s my code:
board =
for i in range(0, 5):
board.append([“O”] * 5)
def print_board(board_in):
for row in board:
print(row)
print(print_board(board))
board = []
for i in range(5):
board.append(["O"] * 5)
def print_board(board_in):
for row in board:
print row #here, it's already handling the **print**ing
print_board(board)
in this exercise, and the board is printed two times.
I had the same thing happen. I changed ‘for row in board’ to ‘for row in board_in’ and it then only printed 5 rows instead of 10.
I think the instructions were messed up. By telling us to make the reference to the list itself, which is named “board” (rather than to the argument of the function, which is named “board_in”), I bet it messed something up in the function.
Also, the function could never be passed a different list other than board, using the code as written according to the instructions. The function specifies an argument, but then the argument never gets used again in the function’s definition (because it is mis-written to directly reference the list ‘board’).
I confirmed this:
Versus if I fix the function to use the argument, the second list will actually print out:
Edit: I just noticed that this time, even with ‘board’ instead of ‘board_in’ it didn’t print 10 rows in a row. Even when I commented out my ‘hi’ list and print, it only printed out 5 rows. Go figure.
I created the following function, which produces the right result in the output, but somehow i get a red cross against the action with no explanation and cannot move forward in the lesson:
board = []
for number in range(0,5):
board.append(["O"]*5)
Up until here it is ok, and below is the function I created whcih generates the right result but isn’t accepted as a correct answer>>>
def print_board(board_in):
for board_in in range(0,25):
print board[board_in]
board = []
for number in range(0,5):
board.append(["O"]*5)
def print_board(board_in):
for board_in in range(0,25):
print board[board_in]
print_board(board)
yes, you see the right result. But the loop is not done yet, which results in an error, which would mean the rest of your program is not going to go well.
I would agree with you. The instructions are calling for use of ‘board’ argument in the FOR loop which is providing desired output in this case. However, it means the whole function ‘print_board’ is not scalable which defies the purpose of it being a function. I’m surprised @codecademy did not correct those instructions so far(?)
Hi, remember that the function has the built in function “print” in its body, then like you just want to print the “board” and the function already does it, you only need to call the function “print_board(board)”, you shouldn’t print the function because this function doesn’t have a return keyword to print, then it doesn’t have anything to print.
You only need to call the function without the “print” keyword, I hope you understand my explanation, I think I’m right.
