Hide... and Seek


#1



def random_row(board):
return randint(0, len(board) - 1)

def random_col(board):
return randint(0, len(board[0]) - 1)


I don't understand that in the "hide" exercise I typed
def random_col(board):
return randint(0, len(board) - 1)
But it changed once I came to the ... and seek exercise(to the code given at top)

What is the exact difference it creates in the code?


from random import randint

board = []

for x in range(0,5):
    board.append(["O"] * 5)

def print_board(board):
    for row in board:
        print " ".join(row)

def random_row(board):
    return randint(0, len(board) - 1)

def random_col(board):
    return randint(0, len(board[0]) - 1)

ship_row = random_row(board)
ship_col = random_col(board)
print ship_col
print ship_row

guess_row = int(raw_input("Guess Row: "))
guess_col = int(raw_input("Guess Col: "))


#2

this code:

def random_col(board):
    return randint(0, len(board[0]) - 1)

is slightly better, if you ever where to create an board which doesn't have the same number of row and columns, this ensures your get the length of column.


#3

How is "len(board)-1" telling us the lenght of the rows and "len(board[0])-1" the length of the columns


#4

len() will give use the length of the list/number of items in the list. given this is our board:

[['O', 'O', 'O', 'O', 'O'], ['O', 'O', 'O', 'O', 'O'], ['O', 'O', 'O', 'O', 'O'], ['O', 'O', 'O', 'O', 'O'], ['O', 'O', 'O', 'O', 'O']]

there are 5 lists inside the list, so len(board) is 5, we subtract one for the fact that list are zero index based

board[0] will give us access to the first row:

['O', 'O', 'O', 'O', 'O']

and len will count the number of items, which again is 5. again we subtract one to compensate for the fact that lists are zero index based


#5

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