<PLEASE USE THE FOLLOWING TEMPLATE TO HELP YOU CREATE A GREAT POST!>
i need your help for a simple exercice in pyhton 2.7
<Below this line, add a link to the EXACT exercise that you are stuck at.>
the exercice is a about strings : you have to check a string under certain condition
the len is bigger or equal 6
4 first characters are equal to the last 4
the 6 th character is R or r
the 3 middle character equal the 3 last characters in inverse sens (abc==cba)
if true --> print Yes
else—> print NO
my code is like that:
str1 = "abff"
#str2="abcdxRdcbM7abcd"
if len(str1) >= 6 and len(str1)%2 != 0 and str1[0:4]==str1[-4:] and str1[5]=="R" or str1[5]=="r" and str1[len(str1)/2-1 : len(str1)/2+2] == str1[:-4:-1]:
print "Yes"
else:
print "No"
<In what way does your code behave incorrectly? Include ALL error messages.>
with str2 everything is ok
but with str1…there is an error:
i have a “index out of range Error”
<What do you expect to happen instead?>
i cant understand why python is simply not entering into the else line and giving me a “NO” answer
…
Len of str1 is under 6 so he should jump to the else line…
```pythonstr1 = “abff”
#str2=“abcdxRdcbM7abcd”
if len(str1) >= 6 and len(str1)%2 != 0 and str1[0:4]==str1[-4:] and str1[5]==“R” or str1[5]==“r” and str1[len(str1)/2-1 : len(str1)/2+2] == str1[:-4:-1]:
print “Yes”
else:
print “No”
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