Help with Call and Response


#1



I'm not exactly sure what to do here. I've tried other ways of writing this by writing n=10 in the second function or removing "return" in the last line. Nothing seems to get it to work. Any help with be appreciated! Thanks!


https://www.codecademy.com/courses/python-beginner-c7VZg/1/2?curriculum_id=4f89dab3d788890003000096#


File "python", line 9
def square(10):
^
SyntaxError: invalid syntax


def square(n):
    """Returns the square of a number."""
    squared = n**2
    print "%d squared is %d." % (n, squared)
    return squared
    
# Call the square function on line 9! Make sure to
# include the number 10 between the parentheses.
def square(10):
    """Returns the square of a number."""
    squared = n**2
    print "%d squared is %d." % (n, squared)
    return squared


#2

the code is:

def square(n):
squared = n**2
print "%d squared is %d." % (n, squared)
return squared

square(10)


#3

I used this code:

def square(n):
    """Returns the square of a number."""
    squared = n**2
    print "%d squared is %d." % (n, squared)
    return squared
    
# Call the square function on line 9! Make sure to
# include the number 10 between the parentheses.
square(10)

#4

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