# Hello

I need help with a exercice, is about Kelvin celsius, thank you
The forecast today is `293` Kelvin. To start, create a variable named `kelvin`, and set it equal to `293`.

The value saved to `kelvin` will stay constant. Choose the variable type with this in mind.

Stuck? Get a hint

Write a comment above that explains this line of code.

Stuck? Get a hint

Celsius is similar to Kelvin — the only difference is that Celsius is `273` degrees less than Kelvin.

Let’s convert Kelvin to Celsius by subtracting `273` from the `kelvin` variable. Store the result in another variable, named `celsius`.

Stuck? Get a hint

Write a comment above that explains this line of code.

Use this equation to calculate Fahrenheit, then store the answer in a variable named `fahrenheit`.

Fahrenheit = Celsius * (9/5) + 32

In the next step we will round the number saved to `fahrenheit`. Choose the variable type that allows you to change its value.

Stuck? Get a hint

Write a comment above that explains this line of code.

When you convert from Celsius to Fahrenheit, you often get a decimal number.

Use the `.floor()` method from the built-in Math object to round down the Fahrenheit temperature. Save the result to the `fahrenheit` variable.

Stuck? Get a hint

Write a comment above that explains this line of code.

Use `console.log` and string interpolation to log the temperature in `fahrenheit` to the console as follows:

``````The temperature is TEMPERATURE degrees Fahrenheit.
``````

Use string interpolation to replace `TEMPERATURE` with the value saved to `fahrenheit`.

Stuck? Get a hint

If you want to check your work, open the hint.

Stuck? Get a hint

By using variables, your program should work for any Kelvin temperature — just change the value of `kelvin` and run the program again.

What’s `0` Kelvin in Fahrenheit?

Stuck? Get a hint

Great work! Kelvin can now publish his forecasts in Celsius and Fahrenheit.

If you’d like extra practice, try this:

• Convert `celsius` to the Newton scale using the equation below

Newton = Celsius * (33/100)

• Round down the Newton temperature using the `.floor()` method
• Use `console.log` and string interpolation to log the temperature in `newton` to the console

Hi @yen_romard!
Can you be more specific with your question? Perhaps post the code you have created with questions about the code?

Otherwise it is very difficult to know where to help.

Thanks!