 # Greater than not equal to 9000

This is my code, it returned the right result but however the solution to this exercise is a bit different

``````def over_nine_thousand(lst):
sum1 = 0

for numbers in lst:
sum1 += numbers
if sum1 >= 9000:
break
if sum1 >= 9000:
return sum1
elif sum1 < 9000:
return sum1
else:
return 0

#Uncomment the line below when your function is done
print(over_nine_thousand([8000, 900, 120, 5000]))  `````````

Hi @fingertier,

The instructions include this:

The function should sum the elements of the list until the sum is greater than `9000` .

Based on that specification, what should be the output from this statement?:

``````print(over_nine_thousand([3000, 6000, 800, 2000]))
``````

Edited on August 22, 2019 to note the following:

The instructions require that we continue to iterate through the elements of the list until the sum goes beyond `9000`, unless we have exhausted the list. However the following `if` block will execute a `break` even if the sum merely equals `9000`:

``````    if sum1 >= 9000:
break
``````

Consider the following list:

``````[3000, 6000, 800, 2000]
``````

When `6000` gets added to the sum, we have reached exactly `9000`. In that case, we should continue to add to the sum, because we have not yet exceeded `9000`, and there are still remaining items in the list.

Given that list, the function, as written in the original post, will return `9000`, when it should instead return `9800`.

With this statement, the function, as given, does produce the correct result:

``````print(over_nine_thousand([8000, 900, 120, 5000]))
``````

However, with this statement it does not:

``````print(over_nine_thousand([3000, 6000, 800, 2000]))
``````