# Get_class_average([lloy]( returned 85.85 instead of 80.55 as expected

#1

get_class_average([lloy]( returned 85.85 instead of 80.55 as expected.

I expected the task to complete.

``````lloyd = {
"name": "Lloyd",
"homework": [90.0, 97.0, 75.0, 92.0],
"quizzes": [88.0, 40.0, 94.0],
"tests": [75.0, 90.0]
}
alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.0, 97.0]
}
tyler = {
"name": "Tyler",
"homework": [0.0, 87.0, 75.0, 22.0],
"quizzes": [0.0, 75.0, 78.0],
"tests": [100.0, 100.0]
}

def average(numbers):
total=sum(numbers)
total=total/float(len(numbers))
float(total)

def get_average(student):
homework=average(student["homework"])
quizzes=average(student["quizzes"])
tests=average(student["tests"])
return tests*0.6+quizzes*0.3+homework*0.1
if score>=90:
return "A"
elif score>=80:
return "B"
elif score>=70:
return "C"
elif score>=60:
return "D"
else:
return "F"
print score

results = []
def get_class_average(students):
for student in students:
result=get_average(student)
results.append(result)
return average(results)``````

#2

Hello @boardplayer44375,

You only need to return result in the `get_class_average()` function. Hope this fixes your problem...

#3

Er.. I don't get it. Is that not what I already am doing, here:
'''
return average(results)
'''

#4

No, the task tells me to:
"Finally, return the result of calling average() with results"

"result" variable contains a single number from the student average. Task requires me to return the average of student averages which I think are stored in a list of results.

#5

You are right, @boardplayer44375. But the results list should be defined inside the function. That should definitely make it work!

#6

Holy mother of jesus that worked. Why?
Does program flow skip the step somehow if it's before the function def? Why?

#7

Oh I guess it's because functions have their own tree of variables/lists/dictionaries.