# For the Record

**mareklmc**#1

**eveat**#2

Hi,

try it without the "name :" part and just print the name. That should fix it.

I guess you will have to leave out "homework: " etc. out too.

Please help I get this message

Oops, try again. The quizzes key does not have the value "[]" in your lloyd dictionary.

lloyd = {

"name": "Lloyd",

"homework": [90.0, 97.0, 75.0, 92.0],

"quizzes": [88.0, 40.0, 94.0],

"tests": [75.0, 90.0]

}

alice = {

"name": "Alice",

"homework": [100.0, 92.0, 98.0, 100.0],

"quizzes": [82.0, 83.0, 91.0],

"tests": [89.0, 97.0]

}

tyler = {

"name": "Tyler",

"homework": [0.0, 87.0, 75.0, 22.0],

"quizzes": [0.0, 75.0, 78.0],

"tests": [100.0, 100.0]

}

students= [lloyd, alice, tyler]

for student in students:

print "name: %s" % student["name"]

print "homework: %s" % student["homework"]

print "quizzes: %s" % student["quizzes"]

print "tests: %s" % student["tests"]

# Add your function below!

def average(numbers):

sum(numbers)

total = sum(numbers)

total = float(total)

tot = total/len(numbers)

return tot

def get_average(student):

homework = average(student["homework"])

quizzes = average(student["quizzes"])

tests = average(student["tests"])

homework = homework * 0.1

quizzes = quizzes * 0.3

tests = tests * 0.6

print homework

print quizzes

print tests

return homework + quizzes + tests

def get_letter_grade(score):

if score >= 90 :

return "A"

elif score >= 80 :

return "B"

elif score >= 70 :

return "C"

elif score >= 60 :

return "D"

else :

return "F"

return get_letter_grade(get_average(lloyd))

students = [lloyd,alice,tyler]

def get_class_average(students):

results = []

for student in students :

results.append(get_average(student))

return average(results)

This is the code