For the Record


#1


Hi, I cant see whats wrong


#2

Hi,

try it without the "name :" part and just print the name. That should fix it.

I guess you will have to leave out "homework: " etc. out too.


#3

Please help I get this message
Oops, try again. The quizzes key does not have the value "[]" in your lloyd dictionary.


#4

cant help you if you dont put the code, and it was what eveat said, thx for the help.


#5

lloyd = {
"name": "Lloyd",
"homework": [90.0, 97.0, 75.0, 92.0],
"quizzes": [88.0, 40.0, 94.0],
"tests": [75.0, 90.0]
}
alice = {
"name": "Alice",
"homework": [100.0, 92.0, 98.0, 100.0],
"quizzes": [82.0, 83.0, 91.0],
"tests": [89.0, 97.0]
}
tyler = {
"name": "Tyler",
"homework": [0.0, 87.0, 75.0, 22.0],
"quizzes": [0.0, 75.0, 78.0],
"tests": [100.0, 100.0]
}
students= [lloyd, alice, tyler]
for student in students:
print "name: %s" % student["name"]
print "homework: %s" % student["homework"]
print "quizzes: %s" % student["quizzes"]
print "tests: %s" % student["tests"]

Add your function below!

def average(numbers):
sum(numbers)
total = sum(numbers)
total = float(total)
tot = total/len(numbers)
return tot
def get_average(student):
homework = average(student["homework"])
quizzes = average(student["quizzes"])
tests = average(student["tests"])
homework = homework * 0.1
quizzes = quizzes * 0.3
tests = tests * 0.6
print homework
print quizzes
print tests
return homework + quizzes + tests
def get_letter_grade(score):
if score >= 90 :
return "A"
elif score >= 80 :
return "B"
elif score >= 70 :
return "C"
elif score >= 60 :
return "D"
else :
return "F"
return get_letter_grade(get_average(lloyd))
students = [lloyd,alice,tyler]
def get_class_average(students):
results = []
for student in students :
results.append(get_average(student))
return average(results)

This is the code