For the record


#1

Code:

lloyd = {
    "name": "Lloyd",
    "homework": [90.0,97.0,75.0,92.0],
    "quizzes": [88.0,40.0,94.0],
    "tests": [75.0,90.0]
}
alice = {
    "name": "Alice",
    "homework": [100.0, 92.0, 98.0, 100.0],
    "quizzes": [82.0, 83.0, 91.0],
    "tests": [89.0, 97.0]
}
tyler = {
    "name": "Tyler",
    "homework": [0.0, 87.0, 75.0, 22.0],
    "quizzes": [0.0, 75.0, 78.0],
    "tests": [100.0, 100.0]
}

students = [lloyd,alice,tyler]

for student in students:
    print student

Console shows this:
{'quizzes': [88.0, 40.0, 94.0], 'tests': [75.0, 90.0], 'name': 'Lloyd', 'homework': [90.0, 97.0, 75.0, 92.0]}
{'quizzes': [82.0, 83.0, 91.0], 'tests': [89.0, 97.0], 'name': 'Alice', 'homework': [100.0, 92.0, 98.0, 100.0]}
{'quizzes': [0.0, 75.0, 78.0], 'tests': [100.0, 100.0], 'name': 'Tyler', 'homework': [0.0, 87.0, 75.0, 22.0]}
None

Error message shows this:
Oops, try again. Did you print out each student's name? It looks like "Lloyd" wasn't printed.

What? Lloyd is clearly printed.


#2

you print the whole dictionary, that is not good enough

Try printing the name only of each student


#3

why is it not good enough?


#4

because its not pretty enough, and dictionaries are unordered, and we want to display the output nicely in order:

name
homework
quizzes
tests


#5

For each student in students, that is, "for student in students", display student data such as: name, homework, quizzes and tests.


#6

that is exactly what i just said?


#7

Got it.
for student in students:
print student["name"]
print student["homework"]
print student["quizzes"]
print student["tests"]

Thanks


#8

#9

Nicely done :slight_smile: