FAQ: Variables and Operators - Operator Precedence

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This community-built FAQ covers the “Operator Precedence” exercise from the lesson “Variables and Operators”.

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This exercise can be found in the following Codecademy content:

[Beta] Learn PowerShell

FAQs on the exercise Operator Precedence

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So, if you add an integer to a boolean you’ll get another boolean?

1 Like
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Yeah, part 3 is confusing. I played with different expressions a bit in Powershell and here are my results:

$expression_3 = 3 + (2 -ne 5) -and (2 * 5 -gt 8)
True
$expression_3 = (2 -ne 5) -and (2 * 5 -gt 8)
True
$expression_3 +=3
4
$expression_3 = (2 -ne 5) + (10 -gt 8) + (3 -lt 5)
3
$expression_3 = (2 -ne 5) -and (2 * 4 -gt 8) + [bool]0
False
(2 -ne 5) -and (2 * 4 -gt 8) + [int]0
False
$expression_3 =[int]((2 -ne 5) -and (2 * 4 -gt 8)) + [int]0
0
(2 -ne 5) + 3 * 5 / 8 % 2
2.875

After talking with a coworker, our conclusion is that implicit typing can lead to unexpected results. Sometimes a boolean is treated mathematically as a 0 or 1, and sometimes it treats integers as booleans and evaluates to a true or false. Fortunately, it seems simple to explicitly type things so that it gives you the result you expect.

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Actually, I think I figured out that it’s due to the order of operations and the function of the operators. -and is evaluated after addition, and the addition operator is mathematical, not logical, as far as I can tell. For example,

> $true + $true
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