FAQ: String, The Exception - Strings Can Look Like Values

This community-built FAQ covers the " Strings Can Look Like Values" exercise from the lesson “String, The Exception”.

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why “tinyDog” is not printing “dalmation” ? If dog is already modified from “chihuahua” to “dalmation”
imagen

  • A string reference will always point to the original object, so “modifying” one reference to a string will not affect other references

This can be explained by the fact that strings are immutable : they cannot be changed after they are created. Anything that appears to modify a string actually returns a new string object.

I didn’t write this, it was from the explanation on the left of the page :slight_smile:

I’m struggling to understand why the highlighted objects would not be equal to each other…

Is this purely down to the fact they have different names? eg. 01 and 02?

TIA

According to Microsoft documentation for ‘Equality Operators’ (link: Equality operators - C# reference | Microsoft Docs)

“By default, two non-record reference-type operands are equal if they refer to the same object”

So, in your code, Object o1 and Object o2 are two different objects, which the computer knows because it was instantiated twice and has 2 different spots in memory and two different names, are not the same object, therefore they cannot be equal with default equality behavior.

If however, you created another object and set it equal to the first object instead of instantiating a new object, then it would pass equality. For example:

Object o1 = new Object();
Object o2 = new Object();
Object o3 = o1;

Console.WriteLine(o1 == o2); //Prints false
Console.WriteLine(o1 == o3); //Prints true