FAQ: Stacks: Python - Stacks Python Review


This community-built FAQ covers the “Stacks Python Review” exercise from the lesson “Stacks: Python”.

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This exercise can be found in the following Codecademy content:

Computer Science

Linear Data Structures

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Ok, I actually didn’t notice this until I saw a similar format in the quiz to follow this… Notice the if: else: statements below:

  def push(self, value):
    if self.has_space():
      item = Node(value)
      self.top_item = item
      self.size += 1
      print("Adding {} to the pizza stack!".format(value))
      print("No room for {}!".format(value))

I don’t recall learning this following. It appears to be an if else statement without the else? Is that right? When did we learn this, so that I can go back to it an review it? I tried to remove the else in above statement to see if it worked that way, and it didn’t. It printed No room for {}!".format(value) each time. So what’s happening?

def pop(self):
    if not self.is_empty():
      item_to_remove = self.top_item
      self.top_item = item_to_remove.get_next_node()
      self.size -= 1
      print("Delivering " + item_to_remove.get_value())
      return item_to_remove.get_value()
    print("All out of pizza.")

  def peek(self):
    if not self.is_empty():
      return self.top_item.get_value()
    print("Nothing to see here!")


Here are two images of what I am talking about to help make sure, in case I typed the code wrong above.



When the action in an if branch is return then there is no need to protect the default (else) case. It can be the next statement following the if.