This community-built FAQ covers the “Creating a Frozenset” exercise from the lesson “Sets”.
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FAQs on the exercise Creating a Frozenset
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We see that output simply because it’s a quirk of python to disambiguate two very similar data structures that perform almost the same tasks but vary ever so subtly.
In this case set() vs frozenset() are both “set-type” data structures, with the difference being the latter cannot be modified.
The same behaviour can be observed between dict() and OrderedDict(), which are both “dictionary-type” data structures. The latter now resides within the collections module so you’d have to import it to use it, and has its own uses that differentiate from a “normal”, and which I cannot even begin to cover here. Nonetheless here’s what the output would look like between the two:
from collections import OrderedDict
In [23]: normal_d = dict(b=2, d=4, a=1, c=3)
In [24]: print(normal_d)
{'b': 2, 'd': 4, 'a': 1, 'c': 3}
In [25]: ordered_d = OrderedDict(b=2, d=4, a=1, c=3)
In [26]: print(ordered_d)
OrderedDict([('b', 2), ('d', 4), ('a', 1), ('c', 3)])
The lesson mentions that we can create an empty frozenset using the syntax:
empty_frozen_set = frozenset()
What would the purpose of this be? If I’m understanding the topic correctly, wouldn’t this just create a set that is permanently empty and can’t be modified? I’m trying to imagine a situation where this could possibly be useful and I’m coming up blank.