FAQ: Sets - Creating a Frozenset

This community-built FAQ covers the “Creating a Frozenset” exercise from the lesson “Sets”.

Paths and Courses
This exercise can be found in the following Codecademy content:

FAQs on the exercise Creating a Frozenset

There are currently no frequently asked questions associated with this exercise – that’s where you come in! You can contribute to this section by offering your own questions, answers, or clarifications on this exercise. Ask or answer a question by clicking reply (reply) below.

If you’ve had an “aha” moment about the concepts, formatting, syntax, or anything else with this exercise, consider sharing those insights! Teaching others and answering their questions is one of the best ways to learn and stay sharp.

Join the Discussion. Help a fellow learner on their journey.

Ask or answer a question about this exercise by clicking reply (reply) below!
You can also find further discussion and get answers to your questions over in #get-help.

Agree with a comment or answer? Like (like) to up-vote the contribution!

Need broader help or resources? Head to #get-help and #community:tips-and-resources. If you are wanting feedback or inspiration for a project, check out #project.

Looking for motivation to keep learning? Join our wider discussions in #community

Learn more about how to use this guide.

Found a bug? Report it online, or post in #community:Codecademy-Bug-Reporting

Have a question about your account or billing? Reach out to our customer support team!

None of the above? Find out where to ask other questions here!

Why when we print frozensets we see the frozenset constructor on the screen? For example,

top_genres = ['rap', 'rock', 'pop']

# Write your code below!
frozen_top_genres = frozenset(top_genres)
print(frozen_top_genres)

This outputs this:

frozenset({'rock', 'pop', 'rap'})

Why is there still frozenset on the screen?

Hello, @ superpythoncoder12

We see that output simply because it’s a quirk of python to disambiguate two very similar data structures that perform almost the same tasks but vary ever so subtly.

In this case set() vs frozenset() are both “set-type” data structures, with the difference being the latter cannot be modified.

The same behaviour can be observed between dict() and OrderedDict(), which are both “dictionary-type” data structures. The latter now resides within the collections module so you’d have to import it to use it, and has its own uses that differentiate from a “normal”, and which I cannot even begin to cover here. Nonetheless here’s what the output would look like between the two:

from collections import OrderedDict

In [23]: normal_d = dict(b=2, d=4, a=1, c=3)
In [24]: print(normal_d)
{'b': 2, 'd': 4, 'a': 1, 'c': 3}

In [25]: ordered_d = OrderedDict(b=2, d=4, a=1, c=3)
In [26]: print(ordered_d)
OrderedDict([('b', 2), ('d', 4), ('a', 1), ('c', 3)])

Hope this answers your question.
Take care

1 Like