FAQ: Math and Date Functions - Date and Time Functions III

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1

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This community-built FAQ covers the “Date and Time Functions III” exercise from the lesson “Math and Date Functions”.

Paths and Courses
This exercise can be found in the following Codecademy content:

Analyze Data with SQL

FAQs on the exercise Date and Time Functions III

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2

I think something wrong with the given solution for this topic.
Offered query

SELECT STRFTIME('%d', order_date), COUNT(STRFTIME('%d', order_date))
FROM bakery
ORDER BY 2;

gives the first date in a table and total number of rows

STRFTIME(‘%d’, order_date) COUNT(STRFTIME(‘%d’, order_date))
16 30

My solution is

SELECT
  STRFTIME('%Y-%m-%d', order_date) order_date,
  COUNT(*) order_quantity
FROM 
  bakery
GROUP BY 
  STRFTIME('%d', order_date);

which results in six dates and quantities of orders on each date

order_date order_quantity
2020-08-16 9
2020-08-17 5
2020-08-18 6
2020-08-19 2
2020-08-20 6
2020-08-21 2
3

Instruction for the last step is:
“Use STRFTIME() with the COUNT() function to find out how many orders were made on each day”
Nothing to indicate that the output should be sorted in descending order.

4

I’m not sure how the count(*) function works so I used this alternate solution and got the same results

with days as (select STRFTIME('%d', order_date) as 'order_day' from bakery)
select order_day, count(order_day) from days
group by order_day
order by 2 desc;

I guess count(*) is self-referential and counts the records as they are displayed in the current query?

5

There’s no need to guess, have a wee look at the docs and you can find the description:
https://www.sqlite.org/lang_aggfunc.html#count

6

It’s kind of common sense bro

7

The task could’ve hinted that we only want the day number though.
I used

‘%Y %m %d’

8

I wrote it like this:

SELECT STRFTIME(‘%Y %m %d’, order_date), COUNT(‘%d’)

FROM bakery

GROUP BY 1

ORDER BY 2 DESC;

Was marked wrong, but got a similar result.