# FAQ: Logical Operators and Compound Conditions - The && Operator

This community-built FAQ covers the “The && Operator” exercise from the lesson " Logical Operators and Compound Conditions".

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## FAQs on the exercise The && Operator

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I keep getting an error saying " Your function should `return` the string `"CLAP!"` if invoked with `TRUE` and `TRUE` . We tested your function with `TRUE` and `TRUE` and expected `"CLAP!"` but instead it returned ``.

However, when I test it, I get the correct response. Here is my function.

function clapYourHands(\$first, \$second){

if( \$first && \$second ){

echo “CLAP!”;

} else{

echo “:(”;

}

}

echo clapYourHands(true,true);

Inside your function, should you `echo` or `return` those strings?

"Your function should `return` the string `"CLAP!" if invoked with TRUE and TRUE"`

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In the lesson it says:

``````TRUE && FALSE;   // Evaluates to: FALSE
``````

Then goes on to say:

The `&&` operator has a higher operator precedence than the `||` operator. This means that in a complex statement that includes both operators, the computer will evaluate the part of the expression with `&&` first:

``````TRUE || TRUE && FALSE // Evaluates to: TRUE
``````

How would that evaluate to TRUE if the && operand has precedence and previously it evalauted to false?

Any help appreciated

Edit. Okay I think I understand this. Precedence had me confused. It’s almost easier for me to think of it as order of operations as opposed to precedence. Precedence had me thinking it was more important not what is done first.

What happens is first the && gets evaluated (giving a FALSE in the above example) then the || which would then evaluate to true because it would be evaluating TRUE || FALSE. I guess that’s why the parantheses help clarify. As it would turn into TRUE || (TRUE && FALSE ).

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