# FAQ: List Comprehension - Divide With Zip

This community-built FAQ covers the “Divide With Zip” exercise from the lesson “List Comprehension”.

Paths and Courses
This exercise can be found in the following Codecademy content:
Analyze data with Python

## FAQs on the exercise Divide With Zip

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Hi, can someone show an example of what they mean by Divide With Zip?
I don’t understand how to use math functions with the Zip command. Thanks.
Here’s the link to the question:

Divide and zip are separate concepts
divide is a function taking in two arguments and returning one value
if you have two lists, you can iterate through them in sync

``````for a, b in zip(list_of_as, list_of_bs):
print(a, b)
``````

map also already has this pairing/grouping behaviour built in:

``````from operator import div
a = [1.0, 2.0, 3.0]
b = [4.0, 5.0, 6.0]
map(div, a, b)  # 0.25 0.4 0.5``````
1 Like

Hello, there are some issues with accepting correct answers. Already reported a bug.

The code:

``````a = [1.0, 2.0, 3.0]
b = [4.0, 5.0, 6.0]

quotients = [b / a for (a, b) in zip(a, b)]
print(quotients)
``````

The program doesn’t accept it, but outputs the correct “print()” statement.
Also shows: “zip argument #1 must support iteration”.
And, at the previous exercise-challenge with summation, everything was ok with this style of coding.

Thank you.

Its best not to get mixed up with the original lists therefore assign it as a different list of each

Here is the solution:

``````a = [1.0, 2.0, 3.0]
b = [4.0, 5.0, 6.0]

quotients = [l1 / l2 for (l1, l2) in zip(b, a)]

print(quotients)
``````
2 Likes

My code:

``````a = [1.0, 2.0, 3.0]
b = [4.0, 5.0, 6.0]
quotients = [num1 / num2 for (num1, num2) in zip(b, a)]
``````

But the solution was

``````a = [1.0, 2.0, 3.0]
b = [4.0, 5.0, 6.0]
quotients = [item2 / item1 for (item1, item2) in zip(a, b)]
``````

Mine works, but I do not know if I was following best practices because the solution given is different.