FAQ: Linked Lists: Python - Linked List Review


This community-built FAQ covers the “Linked List Review” exercise from the lesson “Linked Lists: Python”.

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This exercise can be found in the following Codecademy content:

Computer Science

Linear Data Structures

FAQs on the exercise Linked List Review

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I have a question on the exercise in the Linked List Review page.
It’s about the insert_beginning method, which looks like this when implemented as instructed:

  def insert_beginning(self, new_value):
    print("Function that takes a value parameter")
    new_node = Node(new_value)
    self.head_node = new_node

I wanted to add an alternative insert_beginning method that directly takes a Node as argument:

  def insert_beginning(self, new_node):
    print("Function that takes a Node parameter")
    self.head_node = new_node

To my knowledge, this is method overloading, but for some reason, this doesn’t work.

I tried the following test code:

a = Node(1)
b = Node(2)
d = Node(3)
llist = LinkedList(5)

which gives some pretty strange results because the code only seems to use the original value method.

Thanks for clearing this up! :slight_smile:


I myself am not very proficient in Python, and I only just completed this module.
But upon seeing your question, I tried your method.
It seems to work fine for me, it adds the node fine as a direct argument.

I’m thinking you could achieve what you want with modifying the original method instead, to accept Nodes as direct argument, with a “if isinstance(obj, class)” check
I made and tested the following:

def insert_beginning(self, new_value):
if isinstance(new_value, Node):
self.head_node = new_value
new_node = Node(new_value)
self.head_node = new_node

This way it accepts both inputs. I hope this does not add to the confusion.