FAQ: Learn Python - Pyglatin - Ending Up

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#1

This community-built FAQ covers the “Ending Up” exercise in Codecademy’s lessons on Python.

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#2

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#4

2 posts were split to a new topic: “String Index Out of Range” Error


#5

I don’t understand the second part of the example in this lesson:

s = "Charlie"

print s[0]
# will print "C"

print s[1:4]
# will print "har"

Why when we write

print s[1:4]

It returns only 3 letters (har), but not 4 letters (harl) from the example word above…


#6

[0] = C
[1] = H
[2] = A
[3] = R
[4] = L

It stops TIL position 4, meaning [4] does not get processed.
[0:1] would give you C


#7

Hi,
I am confused by the slice on ‘new_word’.
What we want is the ‘rest’ of word,
word[1:len(word)]
isn’t it?
So, mutating new_word seems a bad idea, and I guess it only works because at the time
new_word = word[1:len(new_word)]...
is called, new_word does not have a length yet,
so - the slice goes to the end of word because in fact no second slice parameter is given??
If new_word already existed, it would contain ‘ay’ etc and would be longer than ‘word’.

So, my question is, should we not better use
new_word = word[1:len(word)]
? Thanks.