FAQ: Learn Python - Pyglatin - Ending Up

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#1

This community-built FAQ covers the “Ending Up” exercise in Codecademy’s lessons on Python.

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#2

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#4

2 posts were split to a new topic: “String Index Out of Range” Error


#5

I don’t understand the second part of the example in this lesson:

s = "Charlie"

print s[0]
# will print "C"

print s[1:4]
# will print "har"

Why when we write

print s[1:4]

It returns only 3 letters (har), but not 4 letters (harl) from the example word above…


#6

[0] = C
[1] = H
[2] = A
[3] = R
[4] = L

It stops TIL position 4, meaning [4] does not get processed.
[0:1] would give you C


#7

Hi,
I am confused by the slice on ‘new_word’.
What we want is the ‘rest’ of word,
word[1:len(word)]
isn’t it?
So, mutating new_word seems a bad idea, and I guess it only works because at the time
new_word = word[1:len(new_word)]...
is called, new_word does not have a length yet,
so - the slice goes to the end of word because in fact no second slice parameter is given??
If new_word already existed, it would contain ‘ay’ etc and would be longer than ‘word’.

So, my question is, should we not better use
new_word = word[1:len(word)]
? Thanks.


#8

I felt like this was a logical problem, too.

EDITED

By saying that new_word is word plus a slice of new_word, we’re using the variable to define itself. I first tried this and it didn’t work. It ran when I replaced “new_word” with just “word.”

My edit is because I said it still worked somehow, but really it didn’t and I was a bit gaslighted because it saved the working code when I ran it again instead of updating it. I refreshed the page and ran the code again with “new_word” and it ran the following error:

Traceback (most recent call last): File “python”, line 9, in <module> NameError: name ‘new_word’ is not defined

So there you go.


#9

I had a question, but just figured it out. Instead of deleting I’ll just leave this below in case anyone else makes the same mistake (which is actually a really simple one!)

Every time I put “new_word = [1:len(new_word)]” into the code
I receive an error message in the console:
new_word = new_word[1:len(new_word)]
^
(for the sake of clarity, the carrot is pointing to the “:”, I tried spacing it out correctly, but once it posts to the forums the carrot goes back to the beginning of the line)

Here is the full if statement with the problem
if len(original) > 0 and original.isalpha():
word = original.lower()
first = word[0]
new_word = [word + first + pyg]
new_word = new_word[1:]
print original

While the above code didn’t work, one I removed the brackets around [word + first + pig] in line 4, the code ran fine. Still trying to understand exactly why that is (I have an idea as to why that might cause an error, but I’m a little confused as to why it caused the particular error that it did). Anyways, if you run into this same problem remove the brackets around [word + first + pig] and your code should run fine.

if len(original) > 0 and original.isalpha():
word = original.lower()
first = word[0]
new_word = word + first + pyg
new_word = new_word[1:]
print original


#10

Why do I have to set new_word equal to the slice [1:len(new_word)]?
I can set it only on print command and it works the same:
print new_word[1:len(new_word)]