FAQ: Learn Python: Function Arguments - Positional Argument Unpacking

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This community-built FAQ covers the “Positional Argument Unpacking” exercise from the lesson “Learn Python: Function Arguments”.

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This exercise can be found in the following Codecademy content:

Learn Python 3

FAQs on the exercise Positional Argument Unpacking

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Write your own function, called myjoin() which takes an arbitrary number of strings and appends them all together, similar to os.path.join() .

def myjoin(*args):
joined_string = ‘’
for arg in args:
# what goes here?
return joined_string

can anyone help with this section of exercise

If we follow the example, we get,

def myjoin(*args):
    return join(*args)

They just want you to fill in:

for arg in arg:
# what goes here?

If you look back to the beginning of the lesson to the example you see:

def shout_strings(*args):
  for argument in args:
    print(argument.upper())

Using that as as example, this was how I did it:

def myjoin(*args):
  my_string = ""
  for argument in args:
    my_string += argument
  return my_string

Thats just what I did… Solved thanks for the input

1 Like

This works on my raspberry pi using Python 3.6.8. The output for exercise 2 matches the output for exercise 1. The Codecademy feedback line, however, returns “Does myjoin() concatenate two strings?” [It worked in the Codecademy interface without an error message sometime later.]

def myjoin(*path_segments):
  full_path = ""
  for path_segment in path_segments:
    join(full_path, path_segment)
  return full_path

answer2 = myjoin(path_segment_1, path_segment_2, path_segment_3)
print(answer2)
def my_join(*paths):
  joined = ''
  for path in paths:
    sep = ''
    if path[0] != '/':
      sep = '/'
    if path[-1] == '/':
      clean_path = path[:-1]
    else:
    	clean_path = path
    joined += sep+str(clean_path)
  return joined

a = 'a/c/sa/'
b = '/b'
c = 'c/'
abc = my_join(a,b,c)
print(abc)

why doesn’t it complete the task? The output is correct.