FAQ: Learn Java: Arrays - String[] args

This community-built FAQ covers the “String args” exercise from the lesson “Learn Java: Arrays”.

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FAQs on the exercise String[] args

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Here in line #12
Newsfeed feed;
What we are doing here? Can anyone please expalain it


I was confused at first too but then it clicked.

Usually when we’ve been creating objects with our constructor methods, we’ve named it and defined it on the same line, for example:

Student james = new Student(19, "English");

but just like variables, we don’t need to define them right away. We can do it on two lines:

Student james;
james = new Student(19, "English")'

So since we don’t know what Strings exactly feed is going to contain yet, we’re merely putting it out there that there is going to be a new object for Newsfeed. Then depending on which if code block runs, we fill in the new object with its info later.


Why does line 32 contain feed.topics? Why reference topics here?

because it use ‘String array’ in class Newsfeed


If we can understand the ‘if, else if, and else’ statements running their respective line of code depending on what the argument is typed in the terminal, we can trace back to the information that is passed up in this entire code.

For example:

Terminal input: java Newsfeed Human

If we start reading our code at the main method, we can trace back this line of code:

feed = new Newsfeed(humanTopics);

This line uses ‘humanTopics’ as an argument, which is then passed to the constructor:

public Newsfeed(String initialTopics) {
topics = initialTopics;

This makes ‘humanTopics’ into ‘topics’:

topics = initialTopics;

which traces back to the Newsfeed class:

String topics;

meaning that to print the array that we choose in the terminal (Human) in the ‘if else’ lines of code, we have to use the ‘feed’ object along with the code ‘topics’ (feed.topics). Otherwise, if we experiment with this, we can try using (feed.humanTopics) instead and go straight to printing it right out of the ‘if else’ statement. The problem with doing this is that not only do we get an error, but logically we are always going to have the ‘humanTopics’ array printed out regardless if we input java Newsfeed Robot in the terminal. I suggest experimenting with this in a notepad with this java class and terminal because Codecademy in this module saves your progress in a manner that might hinder anyone to continuously experiment outside the module curriculum.

I hope this makes it clear for every one and thank you for helping me understand your response about the ‘Newsfeed feed;’.


Reddzl J Tuano

1 Like

After completing the instruction for this exercise I ran the code and typed in the terminal

java Newsfeed Robot

But I all I got was

Error: Could not find or load main class Newsfeed
Caused by: java.lang.ClassNotFoundException: Newsfeed

I don’t know why this comes up.
Please help.


1 Like

Hi icdrasyl,

You will have to first compile the java class in bash using the following command:
javac Newsfeed.java

Thereafter you will be able to execute the following:
java Newsfeed Robot
java Newsfeed Human

1 Like

Hi Everyone,
I dont understand the basic idea of this part. Can some explain this part.

Why it doesn’t run when i run the Newsfeed on terminal without an arguement?

You may refer her answer -> @tashachetty241033936.
And also, I still have a bit problem running in the terminal after doing @tashachetty241033936 instruction. The problem is I can’t seem to print it out.

$ javac Newsfeed.java
Newsfeed.java:31: error: cannot find symbol
symbol: variable feed
location: class Newsfeed

Soon after, I finally figure out that, I need to put the ‘Newsfeed feed;’ right below the ‘public class Newsfeed{}’. I don’t know why though.

Hope this helps anyone that came across the same problem as mine.

Have a nice day :slight_smile:

P/S: Why do we need to put it under class Newsfeed? Can’t we just put it under main() method?Are there any differences from doing that? :confused: If anyone could tell me, I would be so appreciated!

The main method is in the Newsfeed class.

Here's an example...
public class HelloWorld() {
  // This comment is inside the HelloWorld class but is outside of the main method

  public static void main(String[] args) { // This method is inside the HelloWorld class
    System.out.println("Hello world!");

In this exercise, it was said to run the file from passing argument but not mentioned to compile before running in the terminal. To be honest, if you are a beginner, you will ask yourself like,

wait whats happening here, I followed the instructions, but it seems error, why?

I would like to draw attention for that to add this information for beginners: #community #community:Codecademy-Bug-Reporting

There were exercises on how to compile and run files from the terminal in the very first lesson. I’ve attached them below for your convenience.

Thank you for clearing confusion but I am talking about the specific moment of the problem. If the little info was added, coding could have been easier though! Thanks, Anyways!

So I realize leaving the argument empty will not trigger else program.
Is there any way we could interact with blank input?
Like for example, if the user leaves the argument blank, assign string “empty” to the argument.
So it will trigger the else

Thank you in advance!