FAQ: JavaScript Promises - Using Promise.all()

This community-built FAQ covers the “Using Promise.all()” exercise from the lesson “JavaScript Promises”.

Paths and Courses
This exercise can be found in the following Codecademy content:

Web Development

Asynchronous JavaScript

FAQs on the exercise Using Promise.all()

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For number 3 of this challenge, I just can’t figure out the right answer. I feel like I have it correct: Promise.all([checkSunglasses(), checkPants(), checkBags()]);. It’s saying I may have a syntax error, but I don’t think I do. Am I crazy?



You don’t need the () after checkPants etc. Don’t ask me why but it worked for me :slight_smile:

const onReject = (rejectionReason) => {

Is the onReject variable necessary to chain after .then(onFulFill) when checkAvailabilty function already has a string response when the promise is rejected? If so, why?

That did work - though I don’t know why either.

const {checkAvailability} = require('./library.js');

const onFulfill = (itemsArray) => {
  console.log(`Items checked: ${itemsArray}`);
  console.log(`Every item was available from the distributor. Placing order now.`);

const onReject = (rejectionReason) => {

// Write your code below:
const checkSunglasses = checkAvailability('sunglasses', 'Favorite Supply Co.');

const checkPants = checkAvailability('pants', 'Favorite Supply Co.');

const checkBags = checkAvailability('bags', 'Favorite Supply Co.');

Promise.all([checkSunglasses, checkPants, checkBags]).then((onFulfill) =>{

Can someone tell me what is wrong with my code? On Step 4. I get this error.

“Did you pass the onFulfill function into .then() as the success handler? It should be the only argument to .then() . Make sure to pass it in uninvoked.”

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Don’t use the full code from the hint. It’s supposed to be similar to the hint, but not exact.

Promise.all([checkSunglasses, checkPants, checkBags]).then((onFulfill) =>{

If you shorten it to:

Promise.all([checkSunglasses, checkPants, checkBags]).then(onFulfill));

it should work. :crossed_fingers:


Thanks! But I want to know for general knowledge, why was it asking me to shorten it now?

If you leave your code like you had it, it will run when you type node app.js in the console, but the results are different than when you shorten the code to just the function call. I suggest you try it both ways after you complete the exercise to see the difference. I’m not an expert on asynchronous programming, but I believe that is the reason for the somewhat unexpected result you’ll see when you alternate between the two lines of code.

1 Like

:joy: really funny…

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I think it’s because we aren’t assigning it to a value, for example:

let checkItems = Promise.all([checkSunglasses(), checkPants(), checkBags()]);

In that case, I think we need the parentheses because we’re assigning the value of [checkSunglasses(), checkPants(), checkBags()] to checkItems. But in the exercise on codecadamy, it starts with just Promise.all(), so we don’t need the parentheses.

Hope this helps!

1 Like

Where do the onFulfill and onReject come from and how can we use them if they weren’t defined in any of our programs


Having difficulty understanding whats going on with Promises.
Would help to see an explanation using foreground/background, interrupt handlers and pointers.

How I can look at the code in library.js in the terminal? Thanks.

Super late but maybe someone else finds this useful:
I think it is because checkPants etc. aren’t functions, they’re variables. So you aren’t invoking a function directly - you’re passing the variables as arguments to Promise.all. The value of the variables is the result of invoking the checkInventory() function. So you are indirectly invoking a function, but what you’re passing to Promise.all is ‘just’ a value.


To add on to what you said, the function has the console.log commands in it already, so if the function is called it will print to the console without needing the console.log(whileCallingTheFunction). If the function returned strings, then you would need to do the console.log while calling the function, otherwise nothing will be printed to the console.


I agree with what you say, except this part…

I don’t think we can call the variables checkSunglasses , checkPants and checkBags themselves arguments. They are promises returned from calling checkAvailability() three times, and which are then assigned (by reference to their variable names) as individual elements to an array. It’s this array which is passed to the Promise.all() function as its single argument/parameter.

@p.ryan.dorangmail.co, @tochmy, @toskap3

This post answers your question…

You may already know the answer by now, but you have at least two options:

  1. At the top of the the ‘Code Editor’ pane you should see a folder icon and two tabs (one for app.js and one for library.js). If you click library.js, the code should now be visible.
  2. In the bash terminal, there are a variety of commands you can use. The simplest one is probably
    more library.js

They were already defined as functions in the Lesson 10 version of app.js, in the section above the following comment
// Write your code below:
They both just write console.log entries