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just learned about the .remove method. However, if I wanted to remove an item in a list in relation to its index, how do I go about this?
…considering the fact that .remove does not accept any parameter, other than the actual item to be removed.
Thank you! In that case, how would you go about removing all the Mangos in the list? Is the only way to use a “for” loop to look for every mango in the list?
In truth if the list was not referenced elsewhere (and didn’t consume an absurd amount of memory) I’d prefer to create a new list skipping all the values that equal ‘mango’, so-
new_store_order_list = [
element
for element in new_store_order_list
if element != 'mango'
]
The problem with removing multiple values is that the length of the list changes when you remove them, so iterating through that list becomes quite difficult. I think a single pass noting the index of each matching element and then removing them in reverse might be a passable option. Sounds like an interesting task if you wanted to give it a shot .
Just went and completed “Shrinking a List: Remove” and there was no requirement to iterate over the list. We use only the .remove() method to remove “Flatbread” and then later, “Mango”, and attempt to remove “Onions” to see the KeyError that gets raised.
you can use del statement like take a example code:
my_list = ['medicine', 'groceries', 'snacks', 'toys']
# if i want to remove snacks cause im getting fatty so i can:
del my_list[2]
print(my_list)
#in output my snacks will be removed :(
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