# FAQ: Introduction to Linear Algebra - Gauss-Jordan Elimination

This community-built FAQ covers the “Gauss-Jordan Elimination” exercise from the lesson “Introduction to Linear Algebra”.

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## FAQs on the exercise Gauss-Jordan Elimination

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I’m confused about step 3. Why are we adding one half of the values in row 3? I’ve never solved for any variables before in school by adding half of anything.

Not sure if you are still waiting for a reply, but in case you are: you can multiply the coefficients in a row by any number as long as you apply that to all coefficients in the row.

R1: 1 1 -2 | 1
R3: -2 2 1 | 0

Divided by two: 0.5(R3) + R1
(1+ -1) (1 + 1) (-2 + 0.5) | (1 + 0)
=> 0 2 1.5 | 1
=> 2y + 1.5z = 1

R1 Multiplied by two: R3 + 2(R1)
(2+ -2) (2 + 2) (-4 + 1) | 2
=> 0 4 3 | 2
=> 4y + 3z = 2