FAQ: Introduction to Data Frames in R - Filtering Rows with Logic I

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This community-built FAQ covers the “Filtering Rows with Logic I” exercise from the lesson “Introduction to Data Frames in R”.

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I’m just wondering why I can’t pipe a dataframe into a function at the same time as assigning the output to a new variable. Or at least, that’s what I’m trying to do, but maybe that’s not what I’m actually doing.

Example:

artists %>%
rock_groups <- filter(genre == ‘Rock’)

The above doesn’t work, and instead I have to write:

rock_groups <- filter(artists, genre == ‘Rock’)

Can anyone explain why I’m not allowed to do the first, and maybe show me how to use piping correctly to assign the output to a variable?

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3

It can be done like this:

rock_groups <- artists %>% filter(genre == 'Rock')

The artists data frame is piped into the filter function [this is equivalent to filter(artists, genre == ‘Rock’)], and the output is then assigned to the variable rock_groups.

The problems with

artists %>%
rock_groups <- filter(genre == ‘Rock’)

are:

  • artists %>% rock_groups is trying to pipe a data frame into a variable. That isn’t correct.

  • rock_groups ← filter(genre == ‘Rock’) is trying to call the filter function with a condition but no data frame. Then it is trying to assign the result? into a variable.

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