FAQ: Introduction to Data Frames in R - Filtering Rows with Logic I

This community-built FAQ covers the “Filtering Rows with Logic I” exercise from the lesson “Introduction to Data Frames in R”.

Paths and Courses
This exercise can be found in the following Codecademy content:

Learn R

FAQs on the exercise Filtering Rows with Logic I

There are currently no frequently asked questions associated with this exercise – that’s where you come in! You can contribute to this section by offering your own questions, answers, or clarifications on this exercise. Ask or answer a question by clicking reply (reply) below.

If you’ve had an “aha” moment about the concepts, formatting, syntax, or anything else with this exercise, consider sharing those insights! Teaching others and answering their questions is one of the best ways to learn and stay sharp.

Join the Discussion. Help a fellow learner on their journey.

Ask or answer a question about this exercise by clicking reply (reply) below!

Agree with a comment or answer? Like (like) to up-vote the contribution!

Need broader help or resources? Head here.

Looking for motivation to keep learning? Join our wider discussions.

Learn more about how to use this guide.

Found a bug? Report it!

Have a question about your account or billing? Reach out to our customer support team!

None of the above? Find out where to ask other questions here!

1 Like

I’m just wondering why I can’t pipe a dataframe into a function at the same time as assigning the output to a new variable. Or at least, that’s what I’m trying to do, but maybe that’s not what I’m actually doing.


artists %>%
rock_groups <- filter(genre == ‘Rock’)

The above doesn’t work, and instead I have to write:

rock_groups <- filter(artists, genre == ‘Rock’)

Can anyone explain why I’m not allowed to do the first, and maybe show me how to use piping correctly to assign the output to a variable?


It can be done like this:

rock_groups <- artists %>% filter(genre == 'Rock')

The artists data frame is piped into the filter function [this is equivalent to filter(artists, genre == ‘Rock’)], and the output is then assigned to the variable rock_groups.

The problems with

artists %>%
rock_groups <- filter(genre == ‘Rock’)


  • artists %>% rock_groups is trying to pipe a data frame into a variable. That isn’t correct.

  • rock_groups ← filter(genre == ‘Rock’) is trying to call the filter function with a condition but no data frame. Then it is trying to assign the result? into a variable.

1 Like