FAQ: Functions: Lesson - Functions with Pointers

This community-built FAQ covers the “Functions with Pointers” exercise from the lesson “Functions: Lesson”.

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The instruction supply this code block.
In the first line in main() func there’s something which may be an invalid integer declaration.
Did I get it wrong?

void myFunc(int* a){
  *a = *a+2;
  printf("a inside myFunc(): %d\n", *a);
}
 
int main(){
  a = 10;  // < -- RIGHT HERE
  int* aPointer = &a;
  myFunc(aPointer);
  printf(“a in main(): %d\n”, a);
}
2 Likes

I think you’re right, the variable a in main() is not declared.

Screenshot_20221122_094613
Umm, thanks first, im really confused here, can anyone tell me why a in main() = 12 :<<

**Edit: Oh i got it thanks :<<