FAQ: Control Flow in Ruby - Not

This community-built FAQ covers the “Not” exercise from the lesson “Control Flow in Ruby”.

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when using the boolean operator (!) with this chain # boolean_2 = !true && !true

I would expect the expression to output
boolean_2 = true

However, the correct output if ‘false’ - why?

Thanks y’all

1 Like

why did you expect true?

first the not operator (!) is processed, resulting in:

false && false

then && is processed, which results in false.

4 Likes

Hello all, why the following code is true: (700 / 10 == 70)
therefore boolean_3 = !(700 / 10 == 70) is false?
Thank you :slight_smile:

!(700 / 10 == 70)

The expression in the parentheses will be evaluated first.

The division operator / has higher precedence than the equality operator ==, so division will be performed and then the equality comparison will be made.

700 divided by 10 equals 70. Therefore the expression 700 / 10 == 70 simplifies to 70 == 70. This is true.

Then negation is carried out which flips the true to false.

!(700 / 10 == 70)
!(70 == 70)
!(true)
false

Thanks a lot for helping out!