FAQ: Conditionals and Control Flow - Boolean Operators: Precedence


#1

This community-built FAQ covers the “Boolean Operators: Precedence” exercise from the lesson “Conditionals and Control Flow”.

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FAQs on the exercise Boolean Operators: Precedence

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#2

Though there’s an order to the boolean, equation in parentheses come in first right? The computer will read !(3<4 || (5>7 && 6<8)); as false.


#3

I’m confused how the order of operations happens in the example: (!(false) || true && false)
The way I see it the order goes !(false) evaluates to true, turning the equation into (true || true && false), which should then go true || true returns true, and then true && false returns false. So why is the && evaluated before the ||?
I even tested it out in the console by just running System.out.println(true || true && false), which if we’re going left to right should return false, but instead returns true. Can someone explain why that is to me?


#4

Because they are part of the same clause, AND is evaluated first, then OR. Not that it matters, in this instance since OR short-circuits on true.

(!(false) || true && false)

We can safely remove the outer brackets since it contains essentially a single clause (i.e., expression).

!(false) || true && false

NOT will affect only the adjacent expression, and as it is at the top of the precedence chain we can evaluate it first.

true || true && false

AND takes precedence to OR, so we have,

true || false

As mentioned, this is all moot since OR will ignore any operands after a true. The above is true, regardless what was on the right side of OR.


#5

Thank you! That’s definitely good to know. The instructions only said that everything gets operated from left to right (after parentheses) so this distinction was not made clear.