FAQ: Conditional Statements - The switch keyword


#1

This community-built FAQ covers the “The switch keyword” exercise from the lesson “Conditional Statements”.

Paths and Courses
This exercise can be found in the following Codecademy content:

Web Development

Introduction To JavaScript

FAQs on the exercise The switch keyword

There are currently no frequently asked questions associated with this exercise – that’s where you come in! You can contribute to this section by offering your own questions, answers, or clarifications on this exercise. Ask or answer a question by clicking reply (reply) below.

If you’ve had an “aha” moment about the concepts, formatting, syntax, or anything else with this exercise, consider sharing those insights! Teaching others and answering their questions is one of the best ways to learn and stay sharp.

Join the Discussion. Help a fellow learner on their journey.

Ask or answer a question about this exercise by clicking reply (reply) below!

Agree with a comment or answer? Like (like) to up-vote the contribution!

Need broader help or resources? Head here.

Looking for motivation to keep learning? Join our wider discussions.

Learn more about how to use this guide.

Found a bug? Report it!

Have a question about your account or billing? Reach out to our customer support team!

None of the above? Find out where to ask other questions here!


#2

A post was split to a new topic: Why we have to use “break” after default


#4

The last break; at the end of the whole block is necessary? If so, why? There’s no more cases incoming.

Thanks.


#5

You are correct in that assessment. The author wrote it into the SCT so we have no choice but to humor them. Technically, there is no break in the default case since it is the last expression in the switch statement.


#6

I guess, that was a joke :slight_smile: :

Remember to add the break keyword at the end of the default case.

But apart from that, there was a confusing line in the explanation part:

Without the break keyword at the end of each case, the program would execute the code for all matching cases and the default code as well.

Why matching? Wouldn’t it just run till the next break or to the end of the block, if no breaks are met on the way, no matter if case is matched or not?


#7

When a case action does not include return, the switch is still being parsed for other possible matches. Even if none are found, the default case will execute, on top of whatever action was carried out on the first match. break directs control flow to the next statement AFTER the switch body.

Recall that case must match the given switch expression in order for control flow to enter that branch. Only in cases where we wish to include the default case in all instances would we omit the break on each case branch, which is highly unusual.


#8

What are some real-life scenarios where one might want their program to execute multiple cases in one switch code block?