FAQ: Code Challenges: JavaScript Fundamentals - agreeOrDisagree()


#1

This community-built FAQ covers the “agreeOrDisagree()” exercise from the lesson “Code Challenges: JavaScript Fundamentals”.

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This exercise can be found in the following Codecademy content:

Web Development

FAQs on the exercise agreeOrDisagree()

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#3

The question states: write a function that takes in two strings. Shouldn’t first and second be written as strings, such as const agreeOrDisagree (‘first, second’) ??


#4

That is one string, btw. If the function expects two strings, then each would be quoted separately. Are first and second already declared variables with a value? If so, there would be no quotes since we wish to access those values, and not 'first', 'second'.


#5

How come I get an error with this code? I get the right answer and I’ve tested it but I’m still not allow to move forward.


#6

I just realised that “Agree” and “Disagree” were capitalised :pensive: . There should at least be some leeway for capitalisation of strings surely??


#7

if you use a return and wrap the condition in () it will work.

try this…

const agreeOrDisagree = (answer1, answer2) => {return (answer1 === answer2 ? ‘You agree!’ : ‘You disagree!’);}

console.log(agreeOrDisagree(“yep3”, “yep”))


#8

Why doe this work: const agreeOrDisagree = (first, secound) => {
if(first === secound) {return’You agree!’}
else {return ‘You disagree!’}}

but this doesnt?
const agreeOrDisagree = (first, secound) => {
if(first === secound) {console.log(‘You agree!’)}
else {console.log(‘You disagree!’)}}