FAQ: Code Challenge: Loops - Larger Sum


This community-built FAQ covers the “Larger Sum” exercise from the lesson “Code Challenge: Loops”.

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This exercise can be found in the following Codecademy content:

Computer Science

FAQs on the exercise Larger Sum

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I am currently working on exercise #7 in Code challenge - Loops (Python in computer science path).
I don’t understand the output that my function is supposed to have .

In the instruction, it is written:

Create a function named larger_sum() that takes two lists of numbers as parameters named lst1 and lst2 .

The function should return the list whose elements sum to the greater number. If the sum of the elements of each list are equal, return lst1 .

I have put in italic the part that I don’t understand.

In the exercise, we test the function on the list: ([1, 9, 5], [2, 3, 7])

It could be a big help if I could see the final list I should get from the function.



Since the sample lists we are using is List 1 - [1, 9, 5] and List 2 - [2, 3, 7], we should use the for loop to count the sum of numbers in each list first.

Then compare both sums and return the greater one. Or if they are equal, return lst1.

def larger_sum(lst1, lst2):
sum1  = 0 #create new variable for sum of numbers from list 1
sum2  = 0 #create new variable for sum of numbers from list 2
  for number in lst1:
     sum1 += number
  for number in lst1:
     sum1 += number
  if sum1 >= sum2:
     return lst1
     return lst2


We could also use the built-in sum() function:

def larger_sum(lst1, lst2):
  if sum(lst1) >= sum(lst2):
    return lst1
    return lst2


This is what I get, the solution seems to be right, but it still gives me a warning:

Anyone knows why?


line 11:

if summ1 > summ2:

It only returns summ1 if summ1 is larger than summ2.
Else it returns summ2

You should try using >= so that if summ1 is the same as summ2, it will return summ1.


Hi there!

Could you please tell me where I am wrong?

Many thanks,