16 posts were split to a new topic: Why do I need to create a new variable (like count?)

my inefficient-but-it-works solve

```
def divisible_by_ten(nums):
i = 0
for num in nums:
if num % 10 == 0:
i = i + 1
return i
```

More elegant than mine!

Hi guys,

I’m sure i’m going about it it the wrong way but if anyone can give me insights into what’s happening with the code, i’d greatly appreciate it.

From my understanding, my code (at the bottom) should iterate through the entire list however it seems to stop after the first one, can anyone advise as to why (or if it’s doing anything else)?

```
def divisible_by_ten(nums):
count = 0
for number in nums:
if (number % 10 == 0):
count += 1
return count
#Write your function here
def divisible_by_ten(num):
count1 = len(num)
print(count1)
for numbers in list(range((count1))):
print(list(range(count1)))
print(num)
if num[numbers]%10!=0:
continue
new_list =[ ]
new_list.append(num[numbers])
print(new_list)
return len(new_list)
```

I recommend running your code here:

http://www.pythontutor.com/visualize.html#mode=edit

to help you to identify the issue. This allows you to step through your code. You might need to add a function call.

thank you! I’ve used it a fair bit

Still have question left? Or is everything crystal clear now?

```
#Write your function here
def divisible_by_ten(nums):
list = []
for num in nums:
if num % 10 == 0:
list.append(num)
return len(list)
#Uncomment the line below when your function is done
print(divisible_by_ten([20, 25, 30, 35, 40]))
```

Could someone explain to me if this is an advisable solution to this code challenge

That depends, if you are only interested in how many numbers are divisible by 10, and not which numbers that are, i wouldn’t use a list

i would simply use:

```
count = 0
```

then increase count every time your if condition is true

Hello

I dont understand why im only getting 1 in the count as oppossed to 3.

can someone please give me a hand

here is the code

The assignment operators always place the operation ahead of the assignment.

```
+=
-=
*=
/=
//=
%=
**=
```

and so on.