# FAQ: Code Challenge: Lists - More Than N

This community-built FAQ covers the “More Than N” exercise from the lesson “Code Challenge: Lists”.

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This exercise can be found in the following Codecademy content:

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A post was split to a new topic: My solution

2 posts were split to a new topic: Is my indentation wrong?

def more_than_n(lst, item, n):
return (lst.count(item) > n)

2 posts were merged into an existing topic: What ways are there to count the occurrences of an item in a list?

2 posts were split to a new topic: I printed a true string, why doesn’t it pass?

3 posts were split to a new topic: Do I need to count `n`?

A post was split to a new topic: How do I know what I need to count?

A post was split to a new topic: Why doesn’t this code work?

ok so can anyone explain to my why my code which was the inverse of the given solution didnt return False?

def more_than_n(lst, item, n):
if n > lst.count(item):
return True
else:
return False

Hello. I tried implementing the exercise with the for loop:

``````
def more_than_n(lst, item, n):

count = 0

for item in lst:

count += 1

print(count)

if count > n:

return True

else:

return False

``````

In the middle, I put in a print command to check my count and it printed 8 which I know is the wrong count.

Could someone please point out where my error is? Thank you.

This is wiping out the `item` parameter, so there is nothing to count.

Think what it is we are trying to do.

• iterate over `lst`
• compare to `item`
• increase `count` if iteration value matches
• compare `count` to `n`
• return boolean from comparison
``````
def more_than_n(lst, item, n):
count = 0
for x in lst:
if x == item:
count = count + 1

print(count)
return count > n

``````

Ah, gotcha. Thanks a lot Roy. I was not familiar with how the for loop is set up. Makes sense.

1 Like

You’re welcome. Good work. Mark NB in your notes.

I am not sure what this problem is asking for and what does the print statement numbers mean?

Think what it is we are trying to do.

• iterate over lst
• compare to item
• increase count if iteration value matches
• compare count to n
• return boolean from comparison