# FAQ: Code Challenge: Lists - More Frequent Item

This community-built FAQ covers the “More Frequent Item” exercise from the lesson “Code Challenge: Lists”.

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This exercise can be found in the following Codecademy content:

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stuck with the last few questions in this course. Everytime I try and use 1st as an element name I get a syntax error until I change it to first or something similar. Is it an issue with the course or is there a different way to declare a parameter starting with an integer?

Hi seanos90!

I don’t think I have thought or tried to use a number in a variable like this yet. These types of questions :definitions and rules are easy to look up on the internet. Since I haven’t come across this yet (as a newer learner myself) I did some research, and it appears that you can’t have a variable start as a number.

### The Rules

• Variables names must start with a letter or an underscore, such as:
• _underscore
• underscore_
• The remainder of your variable name may consist of letters, numbers and underscores.
• n00b
• un_der_scores
• Names are case sensitive.
• case_sensitive, CASE_SENSITIVE, and Case_Sensitive are each a different variable.

Try to use an underscore before your _1st and see if that will work. The internet is pretty easy to find things like this. Thanks, I learned something new as well!

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This is why we recommend not using `l` as a variable, it can be confused with `1`.

``````lst
``````

is a common name given to `list` objects in sample and exercise code. That is, elle-ess-tee, not one-ess-tee.

As mentioned above, variable names may not begin with a number, but may contain a number.

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Thank you for your reply and Completely get that now, I ended up googling it too after a few more tries. I just don’t get why codecademy would use 1st in the exercises?

The one looks like an elle, but if we check the lesson, I’m betting it is `lst`, not `1st`.

The why of it is representative of `list`, but we should avoid using reserved words as variable names so the author wrote, `lst`. Other authors make it more obvious by using, `my_list` or `alist`, etc.

I make it obvious by using a font where different characters look different

Can anyone tell me why the below code is returning the wrong variable?

I think it has to do with using an IF and then an ELIF statement but I can’t see why that would be:

``````#Write your function here
def more_frequent_item(lst,item1,item2):
if lst.count('item1') >= lst.count('item2'):
return item1
elif lst.count('item2') > lst.count('item1'):
return item2
#Uncomment the line below when your function is done
print(more_frequent_item([2, 3, 3, 2, 3, 2, 3, 2, 3], 2, 3))

``````

I don’t think you need the quotes around item1 and item2 as part of .count(). I think what your function is doing is looking for the strings ‘item1’ and ‘item2’ in the list. It will get 0 for each of these so will always return item1.

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