FAQ: Code Challenge: Aggregate Functions - Code Challenge 8

This community-built FAQ covers the “Code Challenge 8” exercise from the lesson “Code Challenge: Aggregate Functions”.

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This exercise can be found in the following Codecademy content:

Web Development
Data Science

FAQs on the exercise Code Challenge 8

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Why does the solution require the definition of AVG(amount) AS ‘amount’ ? Why is the code not accepted as simply
SELECT AVG(amount)
FROM payments
WHERE status = ‘paid’;

As far as I can tell you don’t need AS 'amount. I used the same code you did and got a success.

Correct, you do not need to use AS 'alias' to generate a result. Using AS just renames a column or table with an alias.

Can someone explaing why when I queried including user_id it only returned the user_id for ‘125’? The average that was provided for this one user id was 18.5362718138556. This is the exact same number that was provided for the query without user_id. I am somewhat confused that the user id for one user can be the same as for the whole table?

SELECT user_id, AVG(amount)
FROM payments
WHERE status = ‘paid’;

SELECT AVG(amount)
FROM payments
WHERE status = ‘paid’;