# FAQ: Booleans and Comparison Operators - User Input: readline()

This community-built FAQ covers the “User Input: readline()” exercise from the lesson “Booleans and Comparison Operators”.

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## FAQs on the exercise User Input: readline()

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Why don’t these run the same? The first is my answer to the exercise, the second is the official solution. I don’t see any reason why they wouldn’t work the same way. Can anybody help?

echo “Hello, there. What’s your first name?\n”;
if (strlen(first_name) > 8) { echo "Hi, {first_name}. That’s a long name.”;
} elseif (strlen(first_name) > 3) { echo "Hi, {first_name}.";
} else {
“Hi, \${first_name}. That’s a short name.”;
}

__________ Official Solution __________________

echo “Hello, there. What’s your first name?\n”;

\$name_length = strlen(\$name);

if (name_length > 8) { echo "Hi, {name}. That’s a long name.";
} elseif (name_length > 3) { echo "Hi, {name}.";
} else {
echo “Hi, \${name}. That’s a short name.”;
}

They would produce the same result. Both are correct.

Except for the missing `\$` here and there.

Do you remember the error message that you received?

Edit : found it.

On the first line : `\$first_name = readline(">> “);`

The second double-quote is what’s causing the problem. Now I’m not sure how you got that. But that double-quote needs to look like the first one.

Edit 2 :

Nope. Not just on that first line actually.

Here as well : `"Hi, {first_name}. That’s a long name.”;`

And here : `“Hi, \${first_name}. That’s a short name.”;`

1 Like

How weird! Not sure how that happened at all. Thanks for your help!

1 Like

So, I noticed I could still get the code to run with or without the {} around the variable name when it was in the middle of the string.

if (name_length > 8) { echo "Hi, {name}. That’s a long name.";
} elseif (name_length > 3) { echo "Hi, {name}.";
} else {
echo “Hi, \${name}. That’s a short name.”;
}

Here’s mine:

if (\$name_length > 8) {
echo “Hi, \$first_name. That’s a long name.”;
} elseif (\$name_length > 3) {
echo “Hi, \$first_name.”;
} else {
echo “Hi, \$first_name. That’s a short name.”;
}

How do I know whether I need to use those curly brackets around a variable like \$first_name?

Why cant we use switch in this scenario?

``````<?php

echo "Hello, there. What's your first name?\n";

\$nameL = strlen(\$name)
switch (\$nameL) {
case \$nameL > 8:
echo "Hi, \$name. That's a long name.";
break;
case \$nameL >= 4:
echo "Hi, \$name.";
break;
case \$nameL >= 3:
echo "Hi, \$name. That's a short name.";
break;
}
``````

Its giving me the following error:

``````ParseError: syntax error, unexpected ‘switch’ (T_SWITCH)

``````

Hey there, @theycallmeholla. Welcome back to the forums, it’s been a while!

Well, you could, I suppose (even though that’s not exactly what’s required by the exercise).

You forgot a semi-colon at the end of `\$nameL = strlen(\$name)`, though. Hence the error.

When I run this code:

``````<?php

echo "Hello, there. What's your first name?\n";
\$name_length = strlen(\$first_name);
if (\$name_length > 8) {
echo "Hi, \${first_name}. That's a long name.";
}elseif (\$name_length > 3) {
echo "Hi, \${first_name}.";
} else {
"Hi, \${first_name}. That's a short name.";
}

``````

I get an error saying " If their name is between `4` and `8` characters (inclusive), your program should print: `Hi, [NAME].` For example, if the user input was `Alexis` your program should print: `Hi Alexis.`"
I have no idea why I am getting this.

This is the official solution:

``````<?php

echo "Hello, there. What's your first name?\n";

\$name_length = strlen(\$name);

if (\$name_length > 8) {
echo "Hi, \${name}. That's a long name.";
} elseif (\$name_length > 3) {
echo "Hi, \${name}.";
} else {
echo "Hi, \${name}. That's a short name.";
}

``````

you forgot to echo there

The console works properly with this, but it’s not accepted as the solution:

``````<?php

echo "Hello, there. What's your first name?\n";
if (strlen(\$name) > 8) {
echo "Hi \$name. That's a long name.";
}
elseif (strlen(\$name) >= 4) {
echo "Hi, \$name.";
}
else  {
echo "\$name. That's a short name.";
}

``````
1 Like

Little bit confused, I can’t get this to pass and the reason I am being given isn’t true. It says, entering ‘Alexis’ should return a response of ‘Hi Alexis’. The thing is it does that.

.

I’m just going to try to move on by replacing my code with the solution (hopefully this will work), but thought it worth mentioning.

Hi, why are we using {} to call the variable? I don’t remember this being explained before, and is not even used on the description example. Some information is missing here.

When I was doing this one I kept getting that same error until I hit the run button in the code editor section. Then it worked fine.