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Hola! Lo siento para mi mal español, pero sí. a_lambda es el parámetro y lamda es el argumento. El parámetro es un marcador de posición para el argumento.
So you nest a block in a block by putting it as the argument? I think that what is exercise is telling us something without actually saying it directly. And it is that you can have a block, more specifically a Proc or a Lambda, as an argument in a method. Why would one need to do that, I do not know yet.
This may seem confusing since we literally just learned what a ‘lambda’ is and now we are ‘interpolating’ blocks in arguments in methods, in which a method can be thought of as a block, but that is what I think is going on here. The lambda is the argument, to the method.
I’m glad you’ve figured it out, @chadw1ck! All I have to contribute is my annoyance with the overuse of the word “lambda” throughout the example - it makes it very hard to follow what is happening. For anyone else, I believe that lambda_demo is the lambda, and a_lambda is a parameter. If I substitute other words to make sense of it, it looks like this:
def demo(my_parameter)
puts "I'm the first!"
my_parameter.call
end
demo(lambda { puts "I'm the second!" })
I don’t understand what’s happening in this exercise or the explanations given above. I’d be very grateful if someone could put it in plain terms for me please.
I understand that we’ve defined a method called lambda_demo, which takes one parameter - (a_lambda), but why do we suddenly call (a_lambda) on line 3?
On line 6 we call lambda_demo with lambda, but how does Ruby know what lambda is? Don’t we need to define lambda somewhere?
Are we defining lambda and a calling it with the same line of code on line 6?
lambda_demo() is the method being called in line 6. The argument to that call is where the lambda (a block) is defined. It is then called within the demo method.
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