# FAQ: Asymptotic Notation: Conceptual - Big Theta (Θ)

This community-built FAQ covers the “Big Theta (Θ)” exercise from the lesson “Asymptotic Notation: Conceptual”.

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Hi there,

In the video he say that 1 divided by 2 is equal to zero but I couldn’t figure out why. I didn’t understand what he said.

Would love a clarification.

Thanks.

2 Likes

I think that this is because N is an integer, and not a float. Since 1/2 is 0.5, we could say that this is equal to 0.

Yea, doesn’t make sense to me either. The explanation is not good.

1 Like

The video mentions that because the number is an integer, when divided it’s equal to zero (because the result is 0.5)

In Python, if you devide 2 integers you will get an integer out of it. And it will always be rounded down. So for example even if you get 0.999 out of a division of 2 integers, the output would be 0

I wrote this code:

``````def function(n):
count = 0
while n/2 != 0:
count += 1
n = n / 2
return print(count)

function(2)
``````

to try out the logic behind the exercise and for some reason the print output would give me a value of 1075.
so I guess the logic that whenever you divide 2 integers will give out a integer back makes no sense to me.
so to fix this problem I tried instead:

``````def function(n):
count = 0
while int(n/2) != 0:
count += 1
n = n / 2
return print(count)

function(2)
``````

only after adding int() in the while statement i could get 1 as a value to be returned… this is a very confusing topic.

why would i need to specify int() in the while statement?
and why would it work without changing the n = n / 2 inside the while loop?

This may be because the course may have been written for Python 2 rather than Python 3 (not completely sure though). In Python 2, the division operator `/` would always return an integer because it did floor division. In Python 3, `/` will return a decimal if applicable. You can use `//` for floor division in Python 3 if you’d like.

Can you post a link to this exercise or explain what the goal of this function is?

2 Likes

By the time i am writing you this Ive noticed I made a mistake while writing the function, it was supposed to be this instead:

``````def function(n):
count = 0
while n != 1:
count += 1
n = n / 2
return print(count)

function(2)

``````

but the fact that I wasn’t getting a integer dividing 2 integer in my previous code was happening… =D

actually…I did not made a mistake on my first post.
The function I wrote there was based on the video not the exercise… (I got confused when I went to look up for the lesson since you asked for the link.)

in the video he does express that function I wrote and I still get the same troubles as before if I do not declare int(n/2) in the while loop

I am quite confused to everything since this is a very complicated topic and I feel like the fact this may be written for python 2 makes me more confused, I am sorry for the double post and all the confusion.

Since I started to learn Python, I meet more and more troubles about Python versions mismatch. I think it is a good habit to put at the beginning of your script which version of Python was used as a comment.

1 Like

Hi, thank you for the explanation. I have a question. When the instructor says “lower bounded power of 2” what does he mean?
What boundary is implied here? Could you please explain?