FAQ: Arrays: Lesson - Looping Through Arrays

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#1

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This community-built FAQ covers the “Looping Through Arrays” exercise from the lesson “Arrays: Lesson”.

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#2

Guys can you help me to resolve the 2nd part of this problem?

Given the integer array arr2 , fill up the array so that each element in the array is four plus the index of the element.

Example:

arr[0] = 4 , arr[1] = 5 , arr[2] = 6 , etc.

#3

That phrasing, “four plus the index” is important. How might you translate that to code?

1 Like
#4

So far i get;

#include<stdio.h> int main() { int arr[] = {3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 20, 22, 26, 28, 29}; int arr2[100]; int i = 0, aux = 1; // Code for Checkpoint 1 goes here for (i = 0; i < 20; i++){ printf("%d\n", arr[i]); } // Code for Checkpoint 2 goes here arr2[0] = 4; printf("%d\n", arr2[0]); for (i = 1; i < 100; i++){ arr2[i] = arr2[0] + aux; printf("%d\n", arr2[i]); aux++; } }
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#5

Hi romanopaulo708735117,

i got to this awmser and i do think that should be right, anyway you should try.

#include<stdio.h>

int main() {
  int arr[] = {3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 20, 22, 26, 28, 29};
  int arr2[100];
    for(int j = 0; j < 100; j++)
    {
      arr2[j] = j + 4; 
      printf("%i\n", arr2[j]);
    }
}

let me know if helped

#6

So I’ve solve this 2nd problem task, and I can access the array elements using printf() but only using the negative indices, if I use positive indices, I keep getting 5, can anyone explain why this is the behavior?
image
This above is my soultion with the added printf() giving me just rows of 100 '5’s.

#7

You have 100 “5” because you assigned 100 times “4+1”.
You should try to use the current index of the array and add 1 to it.

1 Like