FAQ: Arrays - Array Type Inference

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This community-built FAQ covers the “Array Type Inference” exercise from the lesson “Arrays”.

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This exercise can be found in the following Codecademy content:

Learn TypeScript

FAQs on the exercise Array Type Inference

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2

This exercise says that tuples have a fixed length. How can a tuple have a fixed length if you can use the push method to add more elements to it?
let employee: [number, string] = [1, “Steve”];

employee.push(2, “Bill”);

console.log(employee.length); //prints 4

3 Likes
3

That’s a legit question. I ran the code on https://www.typescriptlang.org/ and it printed 4 to the console. I’d like to know what’s going on too. Have you found the answer yet?

4

I also had a problem with this exercise:

The instructions for this exercise aren’t sufficiently clear on how to find the solution.

The 2 rules given are:
1- you are not allowed to use the word Array
2 - you are not allowed to use the characters [ and ].
3 - ***Use the .concat() method and your wits to solve the problem.

The problem:
1- There is no clarification or hint that we have to use the dogUp variable provided
2- Using my wits, as advised, there are other ways to create an inferred string[ ] using .concat( ):

For example (and this was my solution):

let myArr = ‘str’.split(’’).concat( )

console.log(myArr) // [‘s’, ‘t’, ‘r’, ’ ']

5

Can anyone explain the answer to this one? I tried the following but it does not work:
const myArray = dogTup.concat("test","test","test","test");

Thanks!

6

The instructions specify:

Your challenge is to define a variable myArr of the type string[]

You have myArray instead of myArr.

1 Like